TrendingVideosIndia
Opinions | CommentEditorialsThe MiddleLetters to the EditorReflections
UPSC | Exam ScheduleExam Mentor
State | Himachal PradeshPunjabJammu & KashmirHaryanaChhattisgarhMadhya PradeshRajasthanUttarakhandUttar Pradesh
City | ChandigarhAmritsarJalandharLudhianaDelhiPatialaBathindaShaharnama
World | ChinaUnited StatesPakistan
Diaspora
Features | The Tribune ScienceTime CapsuleSpectrumIn-DepthTravelFood
Business | My MoneyAutoZone
News Columns | Straight DriveCanada CallingLondon LetterKashmir AngleJammu JournalInside the CapitalHimachal CallingHill View
Don't Miss
Advertisement

Simplifying single line addition and subtraction

Unlock Exclusive Insights with The Tribune Premium

Take your experience further with Premium access. Thought-provoking Opinions, Expert Analysis, In-depth Insights and other Member Only Benefits
Yearly Premium ₹999 ₹349/Year
Yearly Premium $49 $24.99/Year
Advertisement
Advertisement

Sandeep Tripathi

Advertisement

When we face a problem like the one below, this is usually how we follow it in 3 steps :

EXAMPLE 1

2394,465-77.57-2.013 878.95 = ?

Advertisement

By the classical way

Step1: 2394.465 Step 2: -77.570 878.950 – 2.013

3273.415 -79.583

AND,

STEP 3: 3273.415 – 79.583

Answer 3193.832

By the modern way, we can now solve the problem in a single step , as shown below

TECHNIQUE

1. Start with any of the 4 numbers with equal ease.

2. Just put the correct sign of the given number( or – ).

3. Now the last 2 digits ( units place and 10s place) are being solved for you :

5-0-3-0= 2 and 6-7-1 5 =3 ………….. & so on !

We get : 3193.832 Answer .

Caution

1. Don’t forget to put a zero at required place, like 878.95=878.950

2. In case you get a negative digit at any place, you’re free to borrow 1 from any of the positive next digit.

Here’s how : 4217.86-33.68

Here, at the digits place we have 6-8 =-2, so we need to borrow 1 from next place ie. tens place. Borrowing 1 from 8 leaves 7 there , as you usually do and our units place shall be 10 -2 = 8.

This technique can now be extended to larger numbers also.

Try a few more on your own. Happy solving !

The writer is Lecturer (Physics), Govt. Sr. Sec. School, Sector-7, Panchkula

Advertisement
Show comments
Advertisement